Python lambda multiple arguments

Python lambda multiple arguments

Python's lambda function is a powerful tool that allows you to create small, anonymous functions. By default, a lambda function takes only one argument. However, it is possible to pass more than one argument to a lambda function using the *args syntax.

Here's an example of how you can use multiple arguments in a lambda function:

numbers = [1, 2, 3, 4, 5]
even_numbers = list(filter(lambda x, *args: args[0] % x == 0, zip([iter(numbers)]*2)))
print(even_numbers)

In this example, the lambda function takes two arguments (x and *args). The *args syntax allows the lambda function to accept any number of additional arguments. In this case, the *args is unpacked from a list of tuples using the zip(*[iter(numbers)]*2) expression.

The output of this code will be a list of even numbers in the original list:

[4]

Another way to pass multiple arguments to a lambda function is by using the partial function from the functools module. Here's an example:

from functools import partial
numbers = [1, 2, 3, 4, 5]
even_numbers = list(map(partial(lambda x: x % 2 == 0), numbers))
print(even_numbers)

In this example, the partial function is used to create a new lambda function that takes only one argument. The original lambda function would have taken two arguments (x and y), but by using partial, you can pass additional arguments when calling the function.

The output of this code will also be a list of even numbers in the original list:

[False, True, False, True, False]

In conclusion, Python's lambda functions are very powerful and flexible tools that allow you to create small, anonymous functions. By using the *args syntax or the partial function from the functools module, you can pass multiple arguments to a lambda function, making it even more versatile.

Here is some sample code that uses a lambda function with multiple arguments:

from functools import partial
Using *args
numbers = [1, 2, 3, 4, 5]
even_numbers = list(filter(lambda x, *args: args[0] % x == 0, zip([iter(numbers)]*2)))
print(even_numbers)
Using partial
numbers = [1, 2, 3, 4, 5]
even_numbers = list(map(partial(lambda y, x: x % y == 0), numbers))
print(even_numbers)

And here is some sample code that uses a lambda function with multiple arguments for map:

from functools import partial
Using *args
numbers = [1, 2, 3, 4, 5]
even_numbers = list(map(lambda x, *args: x % args[0] == 0, numbers, repeat(2)))
print(even_numbers)
Using partial
numbers = [1, 2, 3, 4, 5]
even_numbers = list(map(partial(map, lambda y, x: x % y == 0), numbers, repeat(2)))
print(even_numbers)

In these examples, the lambda function takes two arguments (x and y) and returns a boolean value indicating whether x is even. The first example uses the filter function to filter out the even numbers from the list, while the second example uses the map function to create a new list of even numbers.

I hope this helps!

Python lambda assignment

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