python get current date minus 1 day

Margaret 84 Published: 11/27/2024

python get current date minus 1 day

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To get the current date minus one day using Python, you can use the datetime module. Here are a few ways to do it:

Method 1: Using datetime.date.today() and timedelta

import datetime

from datetime import timedelta

Get today's date

today = datetime.date.today()

Subtract one day from today's date

yesterday = today - timedelta(days=1)


print(yesterday)

In this method, we first get the current date using datetime.date.today(). Then, we create a timedelta object with a duration of 1 day and subtract it from the current date to get yesterday's date.

Method 2: Using datetime.datetime.now() and timedelta

import datetime

from datetime import timedelta

Get today's datetime

now = datetime.datetime.now()

Subtract one day from today's datetime

yesterday = now - timedelta(days=1)


print(yesterday)

In this method, we first get the current datetime using datetime.datetime.now(). Then, we create a timedelta object with a duration of 1 day and subtract it from the current datetime to get yesterday's date.

Method 3: Using datetime.date.today() and offset

import datetime
Get today's date

today = datetime.date.today()

Subtract one day from today's date using an offset

yesterday = today + datetime.timedelta(days=-1)


print(yesterday)

In this method, we first get the current date using datetime.date.today(). Then, we create a timedelta object with a duration of -1 day and add it to the current date to get yesterday's date.

All three methods will give you the same result: the date that is one day before today. You can choose the method that works best for your specific use case!

python convert string to date without time

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Python has a built-in datetime module that provides various functions for working with dates and times. To convert a string to a date object in Python, you can use the strptime function from the datetime module.

Here's an example:

import datetime

date_string = "2022-07-25"


date_object = datetime.datetime.strptime(date_string, "%Y-%m-%d").date()


print(date_object)  # Output: 2022-07-25

In this example, we're converting the string "2022-07-25" to a datetime.date object. The strptime function takes two arguments: the input string and a format string that specifies how the input string is formatted.

The format string "%Y-%m-%d" tells Python to expect a date in the format "YYYY-MM-DD". This is just one of many possible formats that you can use with strptime.

If you want to ignore the time component and only convert the date part, you can use the date() method on the resulting datetime object:

import datetime

date_string = "2022-07-25 14:30:00"


date_object = datetime.datetime.strptime(date_string, "%Y-%m-%d %H:%M:%S").date()


print(date_object)  # Output: 2022-07-25

In this example, we're converting the string "2022-07-25 14:30:00" to a datetime.date object. The format string "%Y-%m-%d %H:%M:%S" specifies that the input string is in the format "YYYY-MM-DD HH:MM:SS", where HH:MM:SS represents the time component.

By using the date() method, we're effectively ignoring the time component and only converting the date part to a datetime.date object.

Here are some more examples of common date formats that you can use with strptime:

# YYYY-MM-DD format

date_string = "2022-07-25"


date_object = datetime.datetime.strptime(date_string, "%Y-%m-%d").date()

MM/DD/YYYY format (note the leading zeros)

date_string = "07/25/2022"


date_object = datetime.datetime.strptime(date_string, "%m/%d/%Y").date()

DD/MM/YYYY format

date_string = "25/07/2022"


date_object = datetime.datetime.strptime(date_string, "%d/%m/%Y").date()

I hope this helps! Let me know if you have any further questions.

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