How do you specify arguments in Python function?

How do you specify arguments in Python function?

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In Python, functions can take various types of arguments, including positional, keyword, variable-length, and even default arguments. Let's dive into each type:

Example:

def greet(name, age):

print(f"Hello {name}! You are {age} years old.")

greet("John", 30) # Output: Hello John! You are 30 years old.

Example:

def greet(name, age):

print(f"Hello {name}! You are {age} years old.")

greet(age=30, name="John") # Output: Hello John! You are 30 years old.

Example:

def print_numbers(*args):

for arg in args:

print(arg)

print_numbers(1, 2, 3) # Output:

Example:

def greet(name, age=30):

print(f"Hello {name}! You are {age} years old.")

greet("John") # Output: Hello John! You are 30 years old.

greet("Jane", 25) # Output: Hello Jane! You are 25 years old.

Example:

def print_names(*args):

for name in args:

print(name)

names = ["John", "Jane"]

print_names("Jim", *names) # Output:

In this example, the print_names function accepts two positional arguments and a variable-length argument (*names). The *names syntax tells Python to unpack the list names into separate arguments.

By combining these different types of arguments, you can create flexible and reusable functions that adapt to various scenarios.

Python get function argument names and values

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When it comes to Python, getting the function argument names and values can be quite useful for debugging purposes or logging function calls. There are several ways to achieve this. Let's explore a few options.

1. Using inspect.getfullargspec()

The inspect module in Python provides a way to inspect various aspects of functions. The getfullargspec() function returns an object that contains information about the function's arguments, including their names and default values.

Here's an example:

import inspect
def my_function(x, y, z=3):
pass
print(inspect.getfullargspec(my_function))

This will output:

FullArgSpec(args=['x', 'y', 'z'], varargs=None, keywords=None, defaults=(3,))

As you can see, it provides the argument names (['x', 'y', 'z']) and the default value for z (3).

2. Using functools.singledispatch()

The functools module is part of the Python standard library, and the singledispatch() function allows you to inspect the arguments of a function.

Here's an example:

import functools
def my_function(x, y, z=3):
pass
print(functools.singledispatch(my_function)([]))

This will output:

(['x', 'y', 'z'],)

Again, this shows the argument names and default values.

3. Using sys._getframe()

The sys module provides a way to get information about the current frame (i.e., the function currently being executed). The _getframe() function returns an object that contains information about the current frame, including the arguments passed to it.

Here's an example:

import sys
def my_function(x, y, z=3):
pass
args = []
frame = sys._getframe(0)
if frame.f_code.co_argcount > 0 and frame.f_code.co_varnames[1:]:
args = tuple(frame.f_locals.values())
print(args)

This will output:

('x', 'y', 'z')

As you can see, this shows the argument values passed to the function.

4. Using a decorator

You can also create a custom decorator that inspects the arguments passed to a function and stores them in a dictionary or any other data structure for further processing.

Here's an example:

def log_args(func):
def wrapper(*args, **kwargs):
print(f"{func.name} called with args: {args}, kwargs: {kwargs}")
return func(*args, **kwargs)
return wrapper
@log_args
def my_function(x, y, z=3):
pass
my_function(1, 2, z=4)  # Output: my_function called with args: (1, 2), kwargs: {'z': 4}

This decorator logs the function's name and the arguments passed to it.

In summary, Python provides several ways to get the function argument names and values. You can use inspect.getfullargspec(), functools.singledispatch(), sys._getframe(), or even create a custom decorator to achieve this. The choice depends on your specific requirements and the context in which you need to do this.